In quadrilateral $$ABCD$$, the bisectors of $$\angle A$$ and $$\angle B$$ meet at $$O$$ and $$\angle AOB = 64^\circ. \angle C + \angle D$$ is equal to:

A

$$136^\circ$$

B

$$128^\circ$$

C

$$116^\circ$$

D

$$148^\circ$$