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In a circle with centre O, ABCD isa cyclic quadrilateral and AC is the diameter. Chords AB and CD are produced to meet at E. If $$\angle CAE = 34^\circ$$ and $$\angle E = 30^\circ$$, then $$\angle CBD$$ is equal to:
By the exterior angle property,$$\angle DCA$$ = 30 + 34 = 64$$\angle DAC$$ = 180 - 90 - 64 = 26$$\degree$$$$\angle DAC = \angle CBD$$$$\angle CBD = 26\degree$$
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