IIFT 2019 Question 8

Question 8

AB is the tangent on the circle at point A. The line BC meets the circle at points C and E. Line AD bisects the angle EAC. If angle EAC = $$60^\circ$$ and angle BAC : angle ACB = 2: 5. Find angle ABC :

Solution

Let us consider angle CAB=2x and angle ACB=5x

From Alternate segment theorem,

angle AEC = 2x

In triangle AEC, 60+180-5x+2x=180

3x=60

x=20

In triangle ABC, angle ABC = 180-7*20=40

A is the correct answer.


View Video Solution


Create a FREE account and get:

  • All Quant Formulas and shortcuts PDF
  • 40+ previous papers with solutions PDF
  • Top 500 MBA exam Solved Questions for Free

Comments

Register with

OR

Boost your Prep!

Download App