AB is the tangent on the circle at point A. The line BC meets the circle at points C and E. Line AD bisects the angle EAC. If angle EAC = $$60^\circ$$ and angle BAC : angle ACB = 2: 5. Find angle ABC :

A

$$40^\circ$$

B

$$60^\circ$$

C

$$30^\circ$$

D

None of the options