Question 76

Three boys and three girls are to be seated around table in a circle. Among them the boy X does not want any girl neighbour and the girl Y does not want any boy neighbour. How many such arrangements are possible?

Solution

Position of X and Y is fixed, as all three boys are together with X in center and three girls together with Y in center.

Number of arrangement for boys = $$(3-1)!=2!=2$$

and similarly for girls = $$2!=2$$

$$\therefore$$ Total number of ways = $$2\times2=4$$

=> Ans - (C)

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