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Question 75
Chord AB of a circle is produced to a point P, and is a point onthe circle such that PC is a tangent to the circle. If PC = 18 cm, and BP = 15 cm, then AB is equal to:
Solution
By the property,
$$PC^2 = PA \times PB$$
$$(18)^2 = PA \times 15$$
PA = 324/15 = 21.6 cm
AB = PA - PB = 21.6 - 15 = 6.6 cm
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