Question 73
If the length of a chord of a circle at a distance of 12 cm from the centre is 10 cm, then the diameter of the circle is
Solution
given, OC = 12 cm
AC = CB = 5 cm [line drawn through the centre of a circle bisects a chord ]
therefore, radius OA = $$ \sqrt OC^2 + \sqrt AC^2 $$
= $$ \sqrt 12^2 + \sqrt 5^2 $$
= $$ \sqrt 169 = 13 cm $$
diametre = $$ 2 \times 13 = 26 $$
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