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Question 71

A's age is $$\frac{1}{6}$$th of B's age. B's age will be twice of C's age after 10 years. If C's eighth birthday was celebrated two years ago, then the present age of A must be

Solution

Let B's age = $$6x$$ years and A's age = $$x$$ years and C' present age = 10 years

According to ques,

=> $$6x+10=2\times(10+10)$$

=> $$6x=30$$

=> $$x=5$$

$$\therefore$$ A's present age = 5 years

=> Ans - (A)

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