Question 49

A runs $$1\frac{2}{3}$$ times as fast as B. If A gives B a start of 3 80 in. How far must the winning post be so that A and B reach it at the same time?

Solution

Ratio of the speeds of A and B = 5/3 : 1 = 5 :3

Thus, in race of 5 m, A gains 2 m over B.

2 m are gained by A in a race of 5 m.

80 m will be gained by A in race of $(5/ 2 * 80)$ :

=200 meters

So,

Winning post is 200 m away from the starting point.

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