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A runs $$1\frac{2}{3}$$ times as fast as B. If A gives B a start of 3 80 in. How far must the winning post be so that A and B reach it at the same time?
Ratio of the speeds of A and B = 5/3 : 1 = 5 :3
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
80 m will be gained by A in race of (5/2*80) :
=200 meters
So,
Winning post is 200 m away from the starting point.
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