Question 46

There is a number consisting of two digits, the digit in the units place is twice that in the tens place and if 2 be subtracted from the sum of the digits, the difference is equal to$$ \frac{1}{6}$$ thof the number. The number is

Solution

Let the two digit number be ab,

Where ab = 10a + b, and b = 2*a,

According to the Question,

a+b - 2 = 1/6(10a+b)

Multiply both side by 6,

6a + 6b - 12 = 10a + b

5b = 4a + 12,

Subtracting (b + 6a - 12 ) on both sides,

Substituting b = 2*a,

5(2a) = 4a + 12,

10a = 4a + 12,

Subtract 4a on both sides,

6a = 12,

Divide 6 on both sides,

a = 2,

b = 2*2 = 4,

Therefore , the number is 24

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