Sign in
Please select an account to continue using cracku.in
↓ →
The number of ways in which 6 men and 5 women can dine at a round table if no two women are to sit together is given by
As no two women sit together,
6 men are arranged alternately around the table as shown
These 6 men can be arranged in (6 - 1)! ways (or) 5! ways.
Now, 5 women are arranged in remaining 6 places in $$6_{P_{5}}$$ ways (or) 6! ways.
$$\therefore$$ Total number of ways = 6! × 5!
Hence, option A is the correct answer.
Was this solution helpful?
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation