If$$x^{2}+ y^{2}+ z^{2} $$= xy + yx + zx, then the value of $$\frac{3x^{4}+7y^{4}+5z^{4}}{5x ^{2}y^{2}+7y ^{2}z^{2}+3z^{2}x^{2}}$$
We know that if $$x^{2}+ y^{2}+ z^{2} $$= xy + yx + zx, Then x=y=z
Therefore, substituting x=y=z in given expression $$\frac{3x^{4}+7y^{4}+5z^{4}}{5x ^{2}y^{2}+7y ^{2}z^{2}+3z^{2}x^{2}}$$, we get
= $$\frac{15x^4}{15x^4}$$
=1
Create a FREE account and get:
Day-wise Structured & Planned Preparation Guide
By proceeding you agree to create your account
Free CAT Schedule PDF will be sent to your email address soon !!!
