Solution
$$ a^3 + b^3 - ab - (a^2 - b^2)^2 $$
=$$(a+b)^3-3ab(a+b)-ab-[(a-b)(a+b)]^2$$
=$$1-3ab-ab-(a-b)^2$$
=$$1-4ab-(a^2+b^2-2ab)$$
=$$1-4ab-a^2-b^2+2ab$$
=$$1-(a^2+b^2+2ab$$)
=$$1-(a+b)^2$$
=>$$1-1$$=0
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