If $$ \sec \theta - \tan \theta = \frac{1}{\sqrt{3}} $$ then value of $$ \sec\theta \tan \theta$$ is

Given that  $$ \sec \theta - \tan \theta = \frac{1}{\sqrt{3}} $$  ------> (1)

We know that $$sec^2 \theta - tan^2 \theta $$ = 1

=> $$(sec \theta - tan \theta)(sec \theta + tan \theta)$$ =1

=> $$sec \theta + tan \theta $$ = $$\sqrt{3}$$ ---------> (2)

Solving equations (1) and (2) , we get 

$$ sec \theta $$ = $$\frac{2}{ \sqrt{3}}$$ and $$ tan \theta $$ = $$\frac{1}{ \sqrt{3}}$$

Therefore $$ sec \theta tan \theta $$ = $$ \frac {2}{3} $$