If the co-ordinates of orthocentre and the centroid of a triangle ABC are (—5, 7) and (5, 5), then the circumcentre of the triangle ABC is :
Centroid divides orthocenter and circumcenter in the ratio of 2:1
The co-ordinates of orthocentre and the centroid of a triangle ABC are (—5, 7) and (5, 5)
Let the co-ordinate of circumcenter be (x,y)
5=$$\ \frac{\ 2x-5}{3}\ =\ 5$$ and $$\ \frac{\ 2y+7}{3}\ =\ 5$$
x=10 and y = 4
Hence the circumcenter = (10, 4)
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