In a class, $$83\frac{1}{3}\%$$ of the number of studentsare girls and the rest are boys. If 60% of the number of boys and 80% of the number of girls are present, then what percentage of the total number of students in the class is absent?

Let the total students be x.
Girls = $$83\frac{1}{3}\%x = \frac{250x}{300} = \frac{5x}{6}$$
Boys = x - $$\frac{5x}{6} = \frac{x}{6}$$
Absent boys = (100% - 60% = 40%) of the number of boys
= $$\frac{x}{6} \times \frac{40}{100} = \frac{x}{15}$$
Absent girls = (100% - 80% = 20%) of the number of girlss
= $$\frac{5x}{6} \times \frac{20}{100} = \frac{x}{6}$$
Absent students =$$\frac{x}{15} + \frac{x}{6} = \frac{7x}{30}$$
Percentage absent students = $$\frac{\frac{7x}{30}}{x} \times 100  = 23 \frac{1}{3}$$