A vessel contains a 32 litre solution of acid and water in which the ratio of acid and water is 5 : 3, If 12 litres of the solution are taken out and $$7\frac{1}{2}$$ litres of water are added to it, then what is the ratio of acid and water in the resulting solution?
12 litres of the solution are taken out so, remaining solution = 32 - 12 = 20Â litre
Quantity of acid = 20$$\times \frac{5}{8}$$ = 12.5 litre
Quantity of water = 20$$\times \frac{3}{8}$$ = 7.5 litre
Water added = $$7 \frac{1}{2} = \frac{15}{2}$$ =Â 7.5 litre
Total water = 7.5 +Â 7.5 = 15 litre
The ratio of acid and water in the resulting solution = 12.5 : 15 = 5Â :Â 6Â
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