Question 15

In trapezium ABCD,AB|| CD and AB = 2CD.Its diagonals intersect at O. If the area of $$ \triangle AOB = 84 cm^2$$, then the area of $$ \triangle $$COD is equalto
latek

Solution

$$\frac{area of \triangle COD}{area of \triangle AOB} = \frac{CD^2}{AB^2}$$

$$\frac{area of \triangle COD}{84} = (\frac{1}{2})^2 = \frac{1}{4}$$

$$area of \triangle COD = 21 cm^2$$

So , the answer would be option b)$$21 cm^2$$

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