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In a circle of radius 6 cm, arc AB makes an angle of 114° with centre of the circle O.
What is angle ABO?
In $$\triangle$$AOB, AO = OB (Equal radii)
∴ $$\triangle$$AOB is isosceles.
∴ ∠ABO = ∠BAO = (180°-114°)/2 = 33°
Hence, option D.
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