Given below are two statements:
Statement I : A coin is tossed three times. The probability of getting exactly two heads is 3/8
Statement II: In tossing of 10 coins, the probability of getting exactly 5 heads is 63/256

In the light of the above statements, choose the correct answer from the options given below.

Statement I:

Probability of getting head = P(H) = $$\frac{1}{2}$$

Probability of getting tail = P(T) = $$\frac{1}{2}$$

3 coins are tossed and probability of getting 2 heads = $$3_{C_2}\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)$$ = $$\frac{3}{8}$$

Statement I is true.

Statement II:

10 coins are tossed and probability of getting exactly 5 heads = $$10_{C_5}\left(\frac{1}{2}\right)^5\left(\frac{1}{2}\right)^5$$ = $$\frac{63}{256}$$

Statement II is true

Answer is option A.