DIJIL K
9y ago
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DIJIL K
9y ago
Tushar 9y ago
Hi Dijil
Solving $$x^2 + x - 6 = 0$$
$$\implies (x + 3)(x - 2) = 0$$
Therefore , $$x$$ = 2 or -3
Similarly , $$y^2 - y - 12 = 0$$
$$\implies (y - 4)(y + 3) = 0$$
Therefore , $$y$$ = -3 or 4
The values taken by $x$$ and $$y$$ can be said $$ y \ge x$$
Tushar 9y ago
$$y \ge x$$
Mahesh Kamath 9y ago
RODNEY DSOUZA 9y ago
Mohanapriya 9y ago
X=<Y
NEHA PANDEY 9y ago
X<=Y
Ananya Singh 9y ago
Factors of x will be -3 and 2
Factors of y will be -3 and 4
So While comparing we will get 3 signs between the factors
Hence, No Relation will be there
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