X is a Three digit number and Y is the number formed when the Digits of X are reversed.How many values of X are possible such that the integer Y-X is divisible by 8?

Hi Diwas,
Let the number be xyz.
Number formed on reversing the digits = zyx
zyx-xyz = 8k
100z+10y+x-(100x+10y+z) = 8k
99(z-x) = 8k
z-x = 0,8
When z-x = 8, there is only one solution of (z,x) = (9,1) and y can take ten values from 0-9.
When z-x = 0, there are 9 solutions (z,x) = (1,1)-(9,9) and y can take ten values from 0-9.
Total Solutions = (10*1)+(9*10) = 100