What will be remainder if ((4^47)^23)÷25

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Multiply the powers 47x23=1081 find the power of 4 which when divided by 25(denominator) leaves +1 or -1 4^5=1024/25=-1 now break 1081 in parts so that we can divide it by 5(power of 4) so (4×(4^5)^216)/25 (4x(1024)^216)/25 (4×(-1)^216)/25 4×(+1)/25 (-1 raised to even power is +ve) so 4/25 remainder is 4

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