What will be remainder if ((4^47)^23)÷25

Please help

24

Multiply the powers 47x23=1081
find the power of 4 which when divided by 25(denominator) leaves +1 or -1

4^5=1024/25=-1

now break 1081 in parts so that we can divide it by 5(power of 4)

so (4×(4^5)^216)/25

(4x(1024)^216)/25

(4×(-1)^216)/25

4×(+1)/25 (-1 raised to even power is +ve)

so 4/25 remainder is 4