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8 years, 5 months ago
8 years, 5 months ago
question will not be on finding the actual answer for this. It might be to find last 2 digits or the last digit. If its to find the last digit then we need to remember that last digit for 3^n will repeat with cycles of 4 (3,9,7,1). If its last 2 digits then it would be easier to convert it into 81^n, so that would give 9 * 81^18. For 81^18 last two digits will be 41. 41*9 gives 369, so last 2 digits will be 69
8 years, 5 months ago
There will not be any questions where you will be asked to find the value of something as big as this. If you can post the entire question then I will be able to help you better as may be the question wanted to test you on some logic. This could understood only by looking at the options.
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