two trains started simultaneously, at 11:00 am , from delhi to Jaipur moving towards Jaipur and Delhi respectively and cross each others at 3:00 pm. If the train starting from. Jaipur reached its destination 88 minutes before the other train, when did the train starting from Delhi reach Jaipur

(t1 . t2 )^1/2

Is this the formula?

time taken for trains to cross each other = 4hrs = (t1 . t2)^1/2
where t1 = time taken by train 1 to reach jaipur after meeting = t
t2 = time taken by train 2 to reach delhi after meeting = t+88

solve to get t = 200 mins
so t+88 = 288 mins = 4hrs 48 mins

time of arrival = 3pm + 4hr 48 min = 7:48pm

Hii ayush , can you post the complete solution .plz

07:48 PM..par janna kyon chahte ho,koi saman chut gaya hai kya