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Aditya G

9y ago

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?


A. 42, 33

B. 42, 36

C. 44, 33

D. 44,36

4

sorabh 9y ago

let 1st marks is x

2nd marks is x+9

2x+9 *56/100=x+9

112x/100+ 504/100=x+9

12x/100=396/100x

x=33

1st marks is 33 and 2nd is 42

Vignesh 9y ago

To keep it simple  it's  already  said one got 9 marks more than other. Out of the options  given only option A  satisfies the condition 

DIJIL K 9y ago

A. 42,33

NEHA PANDEY 9y ago

(X+9)=(X+(X+9))*56%

X=33, OTHER=42(33+9)

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