Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?

A. 42, 33

B. 42, 36

C. 44, 33

D. 44,36

To keep it simple  it's  already  said one got 9 marks more than other. Out of the options  given only option A  satisfies the condition 

(X+9)=(X+(X+9))*56%

X=33, OTHER=42(33+9)

A. 42,33

let 1st marks is x

2nd marks is x+9

2x+9 *56/100=x+9

112x/100+ 504/100=x+9

12x/100=396/100x

x=33

1st marks is 33 and 2nd is 42