[Download PDF] TS ICET 2015 Paper with Solutions

Instructions

For the following questions answer them individually

Question 131

For $$\triangle ABC$$ with vertices A(4, 2), B(6, 5) and C(1, 4) the length of the median through A is

Video Solution

Question 132

If A (k, -3), B (2, -5) and C (-1, -8) lie on a line, then AB : BC =

Video Solution

Question 133

For statements p and q, the tautology among the following is

Video Solution

Question 134

If p and q are statements, then the inverse of $$p \rightarrow q$$ is

Video Solution

Question 135

If $$I_k = \left\{x \epsilon R: 0 < x < \frac{1}{k}\right\}$$ for k = 1, 2, 3, ....... then $$\bigcap_{k=1}^{\infty}I_k = $$

Video Solution

Question 136

For sets A, B and C, $$A - (B \cup C) =$$

Video Solution

Question 137

If $$f: R \rightarrow R$$ and $$g : R \rightarrow R$$ are defined by $$f(x) = 2^x$$ and $$g(x) = x^2$$ for each $$x \epsilon R$$, then
$$\left\{x \epsilon R : (fog)(x) = (gof)(x)\right\} =$$

Video Solution

Question 138

The length of the line segment intercepted between the axes by the line joining (6, -4) and (-3, 8) is

Video Solution

Question 139

The angle between the lines 2x + 3y = 5 and 2(x - 1) + 3(2 + y) = 6 is

Video Solution

Question 140

$$\frac{2 \tan 30^\circ}{1 + \tan^2 30^\circ} =$$

Video Solution

CAT Content

TS ICET 2015

For $$\triangle ABC$$ with vertices A(4, 2), B(6, 5) and C(1, 4) the length of the median through A is

If A (k, -3), B (2, -5) and C (-1, -8) lie on a line, then AB : BC =

For statements p and q, the tautology among the following is

If p and q are statements, then the inverse of $$p \rightarrow q$$ is

If $$I_k = \left\{x \epsilon R: 0 < x < \frac{1}{k}\right\}$$ for k = 1, 2, 3, ....... then $$\bigcap_{k=1}^{\infty}I_k = $$

For sets A, B and C, $$A - (B \cup C) =$$

If $$f: R \rightarrow R$$ and $$g : R \rightarrow R$$ are defined by $$f(x) = 2^x$$ and $$g(x) = x^2$$ for each $$x \epsilon R$$, then$$\left\{x \epsilon R : (fog)(x) = (gof)(x)\right\} =$$

The length of the line segment intercepted between the axes by the line joining (6, -4) and (-3, 8) is

The angle between the lines 2x + 3y = 5 and 2(x - 1) + 3(2 + y) = 6 is

$$\frac{2 \tan 30^\circ}{1 + \tan^2 30^\circ} =$$

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If $$f: R \rightarrow R$$ and $$g : R \rightarrow R$$ are defined by $$f(x) = 2^x$$ and $$g(x) = x^2$$ for each $$x \epsilon R$$, then
$$\left\{x \epsilon R : (fog)(x) = (gof)(x)\right\} =$$