If $$ab \neq 0$$ and $$a * b = \frac{1}{ab} - 1$$, then $$\sum_{k=1}^{2015}\left(\frac{1}{k^2} * k\right) =$$

A

$$1008 \times 2015$$

B

$$1007 \times 2015$$

C

$$1006 \times 2015$$

D

$$0$$