There are two containers having mixture of hydrochloric acid and water. In container 1, the ratio of hydrochloric acid and water is 1:2 and in container 2 the ratio of hydrochloric acid and water is 4:1. Find the amount of the mixture that should be taken from container 1 in order to make 28 litres…

Question

There are two containers having mixture of hydrochloric acid and water. In container 1, the ratio of hydrochloric acid and water is 1:2 and in container 2 the ratio of hydrochloric acid and water is 4:1. Find the amount of the mixture that should be taken from container 1 in order to make 28 litres of a mixture containing equal amount of water and hydrochloric acid. (In litres)

Pooja Panikkar · Answer

is the answer 18 ?

sourav prasad · Answer

v1 = volume from container 1, v2 = volume from container 2
volume of water after mixing = volume of acid after mixing.
Using alligations :
4v2/5 + v1/3 = v2/5+2v1/3     ---------- eq 1
v1 + v2 = 28  ----------- eq 2
On solving you will get v1 = 18, v2 = 10.

Himanshu Rai · Answer

18L from container 1 and 10L from container 2.

Geethendra Kumar · Answer

Hey! dear Mr. Sourav, Understood. Thanks Man.

Geethendra Kumar · Answer

Yes dear Ms. Pooja and Mr. Himanshu. Can any one please explain the answer?

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