the time taken to perform a job by a and b together is 10 days. the same job is performed by b and c in 8 days and the same job done by a and c in 14 days. find the individual time taken by all three men working alone to complete the same job

a=560/13, b=560/43, c=560/27

LCM of (10,8,14) = 280 . 280/10 =28(a+b works per day), 280/8=35(b+c works per daily), 280/14=20(c+a works daily) . a+b-b-c-c-a =-27 . -2c=-27. c=13.5,a=6.5, b=21.5(These are works per day individually) . Then divide each with 280, which is total work and you will get your answer .