Jesteen Wrangler
CAT Preparation Community 10y ago
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Jesteen Wrangler
CAT Preparation Community 10y ago
Srikanth LingamneniFaculty 10y ago
@karan, got it almost right, but forgot to exclude the cases where all the 6 birthdays fall in one month.
Hence the probability is (12c2*2^6 - 2)/12^6
Karan Bajpai 10y ago
(12c2*2^6)/12^6??
Karan Bajpai 10y ago
@srikanth thanks for correcting brother...bt shudnt it be 12c2(2^6-2)/12^6
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