the difference in the angles of a rhombus is 60.what is the ratio of the length of the diagonals of the rhombus?

Let one of the angles of the rhombus be x then other will be x+60. Now it is given that 2x+2x+120 = 360
So 4x =240 => x =60. So angles of the rhombus are 120, 60, 120, 60. Diagonals of rhombus intersect at 90 degrees.
so a 30 60 90 right angled triangle is formed. One of the diagonals is of length x and other is rt 3 x so required ratio is rt 3
Hope that helps