the base angle of an isoseles trapezium is 45 degree.if the shorter side and both the equal side are 10cm each.what is the area of the triangle?

Given, In an Isosceles Trapezium ABCD, angle A = angle B = 45° Then angle C = angle D = 135° Area of a trapezium is given by 1/2*h(a+b) On solving we get the area 50(sqrt2 + 1)