pedanaboina jhansi
CAT Preparation Community 10y ago
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pedanaboina jhansi
CAT Preparation Community 10y ago
Pv Aaditya 10y ago
Hi,
The sum of the first 100 positive integers is 100*101/2
So, required average = (100*101/2)/100 = 101/2 = 50.5
Kouts Km 10y ago
the avg of first and last terms of AP...that is (100+1)/2 would be the avg of the sum of AP
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