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Raj Mankar
CAT Preparation Community 4y ago
The 4800th term of the sequence 1, 3, 3, 3, 5, 5, 5, 5, 5, 7, 7, 7, 7, 7, 7, 7, 9, ………… will be
4
ashwin vijay 4y ago
70 is the answer.
tushaar siddhartha 4y ago
139 is the answer
here the term is 70th odd num so its 2n-1 where n is 70
Sivarishi 4y ago
70 th
Hardik Mahajan 4y ago
139 is the term. The Sum of n odd numbers is n square. That means the sum till the 70th bracket is going to be 4900. The terms in the 70th bracket are going to be 2n-1 aka 2(70) -1 = 139. 139 terms written 139 times which means quite obviously 4800th term is also going to be 139. Hence 139 is the answer
