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2 years, 9 months ago
The 4800th term of the sequence 1, 3, 3, 3, 5, 5, 5, 5, 5, 7, 7, 7, 7, 7, 7, 7, 9, ………… will be
2 years, 9 months ago
139 is the term. The Sum of n odd numbers is n square. That means the sum till the 70th bracket is going to be 4900. The terms in the 70th bracket are going to be 2n-1 aka 2(70) -1 = 139. 139 terms written 139 times which means quite obviously 4800th term is also going to be 139. Hence 139 is the answer
2 years, 9 months ago
139 is the answer
here the term is 70th odd num so its 2n-1 where n is 70