SNAP Mock Test by SIBM Pune

The sentence, in its current form, implies that the lights went out while they were reading the novel i.e, that the lights were reading the novel. We need to keep the form and tense intact and write the correct event description. Since the speaker should be the subject reading the novel, the main clause would be: "While I was reading the novel". The supporting modifier is correct. The sentence would be: "While I was reading the novel, the lights suddenly went out." 

When describing the object, the word "scissors" is used. It is used in any use-case as the scissors are a pair of blades. "Scissor" is an incorrect use and the correct answer is option A.

When converting a sentence from the active to the passive form, the subject becomes the object and vice versa. The tense structure of past perfect continuous (had-been-verbing) will change to (had-been-being-past participle-by-subject). Therefore, the correct form of the sentence in passive form will be: The papers had been being corrected by the teacher before the power went out.

In this sentence, the clause after the comma — “who he was told had already resigned” — contains the word functioning as the subject of the verb had resigned. Although it follows 'on the consultant,'  which might suggest an object form like whom, the grammatical role within the clause determines the choice. 

Since 'who' performs the action (had already resigned), the correct sentence is:
“The director asked for a report on the consultant, who he was told had already resigned.”

If 'whom' were used, it would incorrectly suggest that the word is receiving an action within the clause, ie, suggest it’s the object of a verb, which it isn’t.

In the clause “you think will use it best,” the word filling the blank functions as the subject of the verb “will use.” Even though the blank comes after the preposition 'to', which normally takes an object (whom or whomever), the grammatical role within the clause determines the choice. Since the pronoun acts as a subject inside the clause (“whoever will use it best”), “whoever” is correct. We use “whoever” instead of “who” because the word is part of a larger clause: “whoever will use it best”, which functions as the object of the preposition to, while inside that clause it also acts as the subject of will use. “Whoever” can play both roles at once (object of the outer clause and subject of the inner one), but “who” cannot.

So the full sentence reads: “Give the award to whoever you think will use it best.

In this sentence, “the pen” represents writing or peaceful expression, while “the sword” represents war or violence. The words are not meant literally but as symbols for the ideas they are closely associated with. This substitution of one word for another that is closely related in meaning is what defines a 'metonymy'. The correct choice will therefore be option B. 

The word apoplectic refers to someone who is extremely angry or furious, often to the point of being speechless or losing control. Therefore, its opposite would describe a state of composure or tranquillity, which is best captured by the word calm. While 'relaxed' is close in meaning, 'calm' more directly contrasts with the intense anger implied by 'apoplectic'. Hence, the correct choice will be option A. 

The word foist means to force something upon someone, often deceitfully or without their consent. It carries a negative connotation, implying that something unwanted or inferior is being imposed. Among the options, impose best captures this idea of forcing something on someone. The other options don’t quite fit the meaning. The correct choice is therefore option B. 

The idiom "cut to the quick" refers to causing someone intense emotional pain or distress, often by saying or doing something that strikes at their most sensitive feelings. The correct choice will therefore be Option A: To hurt someone deeply in their emotions. 

The correct spelling for the word is COMMITTEE, which matches option A. Hence, option A is the correct choice. 

The phrase “No sooner had we…” is used to indicate that one event happened immediately after another, emphasising quick succession. It is typically followed by “than” and then the second action. Of the options given, the sentence is best completed as:  “No sooner had we passed the cave than a sudden roar emerged from within”. This is both grammatically correct and contextually meaningful. The other options either break the sequence of immediate events or do not logically follow the cause-and-effect or time pattern implied by “no sooner… than.”

The tense of the sentence inside the inverted commas [reported speech] is Simple Present, and the tense of the reporting verb is past. This means that when converting to indirect, the reported speech will become past simple. Hence, the correct conversion will be: "I told him that he needed to get it fixed or he would face a lot of trouble soon ", which is option B. 

[ 'he'll' means 'he will', which becomes 'he would' in the change ]

The error lies in the verb 'make', which should agree in number with its singular subject, 'courage'. Since courage is a singular noun, the correct verb form is makes. Therefore, the sentence should read:

“Even when we run the risk of losing our lives, courage makes us defend what is right and oppose what is wrong.”

The word oppose is already correct because it properly follows us defend… and oppose, both in base form after 'makes us'. [Parallel construction]

After S1 states Mao’s view of contradiction as the engine of development, R logically grounds that view in China’s specific conditions (semi-colonial, semi-feudal economy and peasant centrality), showing why Mao couldn’t copy the Russian path. P then points to his essays (On Contradiction, On Practice) as the vehicles through which he operationalised dialectical materialism for strategy and ideology. S elaborates the method’s content by listing the opposing pairs Mao sought to balance (theory/practice, leadership/mass line, etc.). Q finally generalises the political payoff that progress toward socialism depends on identifying and resolving contradictions, smoothly priming S2, which summarises dialectical materialism as the cornerstone guiding both tactics and the continuous struggle.
The most appropriate order should therefore be RPSQ, which is option D.

The sequence follows $$n^2+1$$ for n = 2,3,4,5,6,7:

$$2^2+1=5$$

$$3^2+1=10$$

$$4^2+1=17$$

$$5^2+1=26$$

$$6^2+1=37$$

$$7^2+1=50$$

Now, we can clearly notice that 38 is the incorrect term. It should be 37.

Explanation: first letters are at positions 1, 3, 6 (differences +2, +3 → next +4 → 10 → J).

Second letters are 26, 24, 21 (differences −2, −3 → next − 4 → 17 → Q).

So the next pair is JQ.

Sunita's original position from the left = N − 15 + 1 = N − 14

After swapping, Rohan takes Sunita's place and becomes 20th from the left, so N− 14 = 20

Hence, N = 34

Step 1: Start at A: (0,0).

Step 2: 10 km East = (10,0).

Step 3: Turn right (facing South) and 5 km = (10, −5).

Step 4: Turn right (facing West) and 10 km = (0, −5).

Step 5: Turn left (from West, left = South) and 5 km = (0, −10).

So point B is at (0, −10) relative to A — that is, 10 km South of A.

We know that A = police, C = teacher. That leaves {doctor, lawyer, banker} for B, D, E.

B is neither a doctor nor a lawyer, so B must be the banker.

1: Jumbo (Jum...) comes before Juncture (Jun c...) because 'm' < 'n'.

2: Among Juncture, Junior, Justice: compare next letters after "Jun" — 'c' (Juncture) < 'i' (Junior) < 's' (Justice).

Hence, the correct order should be 3. Jumbo, 1. Juncture, 4. Junior, 2, Justice

It is given, C sits third to the right of G and G sits at one of the extreme ends of the line.

So, G must sit at the left most end of the line.

So, the arrangement will be like:

G __ __ C  __ __ __

Now A is immediate neighbor of C and B sits second to the left of A.

This means, B must be on immediate right of C.

So, the arrangement will be like:

G __ B  C A  __ __

Now, two people sit between B and F.

So, the arrangement will be like:

G __ B  C  A  F  __

Now, E is not an immediate neighbor of G.

So, the final arrangement is:

G  D  B  C  A  F  E

So, the person sitting at extreme right end of line is E.

It is given, C sits third to the right of G and G sits at one of the extreme ends of the line.

So, G must sit at the left most end of the line.

So, the arrangement will be like:

G __ __ C __ __ __

Now A is immediate neighbor of C and B sits second to the left of A.

This means, B must be on immediate right of C.

So, the arrangement will be like:

G __ B C A __ __

Now, two people sit between B and F.

So, the arrangement will be like:

G __ B C A F __

Now, E is not an immediate neighbor of G.

So, the final arrangement is:

G D B C A F E

So, the position of E with respect to C is that E is third to the right of C.

It is given, C sits third to the right of G and G sits at one of the extreme ends of the line.

So, G must sit at the left most end of the line.

So, the arrangement will be like:

G __ __ C __ __ __

Now A is immediate neighbor of C and B sits second to the left of A.

This means, B must be on immediate right of C.

So, the arrangement will be like:

G __ B C A __ __

Now, two people sit between B and F.

So, the arrangement will be like:

G __ B C A F __

Now, E is not an immediate neighbor of G.

So, the final arrangement is:

G D B C A F E

So, the person exactly in the middle of the line is C.

In both the codes, 'go to school' and 'study in school', 'school' is the common word and also 'ma' is the common code.
Also, both the words appear in the same position.

So, the correct code is 'ma', Option C.

We know the angle between hour hand and minute hand is given by the formula: $$\left|30h-\dfrac{11m}{2}\right|$$
Here, $$h=3$$
So, either, $$30h-\dfrac{11m}{2}=60$$
or, $$30\times\ 3-\dfrac{11m}{2}=60$$
or, $$\dfrac{11m}{2}=30$$
or, $$m=\dfrac{60}{11}=5\ \dfrac{5}{11}$$

Or,$$\dfrac{11m}{2}-30h=60$$
or, $$\dfrac{11m}{2}-30\times\ 3=60$$
or, $$\dfrac{11m}{2}=60+90=150$$
or, $$m=\dfrac{150\times\ 2}{11}=\dfrac{300}{11}=27\ \dfrac{3}{11}$$

Amongst the given options, option C is the correct answer.

Number of days between February 29, 2024 and February 29, 2028 = $$365+365+365+366$$
Now, $$365\equiv 1 \text{ mod }7$$
And, $$366\equiv 2 \text{ mod }7$$
So, $$365+365+365+366\equiv (1+1+1+2) \text{ mod }7$$
So, number of odd days = 5
Now, 5 days after Thursday is Tuesday
So, February 29, 2028 is Tuesday.

The clock loses 3 minutes every 2 hours.

So, it loses 60 minutes every 40 hours.

or, 1 hour every 40 hours.

Now between 12:00 noon on Monday and 6:00 PM on Wednesday, number of hours = $$24+24+6=54$$ hours

So, number of hours lost in 54 hours = $$\dfrac{1}{40}\times\ 54=\dfrac{27}{20}$$ hours

Now, $$\dfrac{27}{20}$$ hours = $$1\ \dfrac{7}{20}$$ hours

Now, $$1$$ hour and $$\dfrac{7}{20}$$ hours = $$\dfrac{7}{20}\times\ 60\ =21$$ minutes

So, time which the clock will show is 6:00 PM - (1 hour + 21 minutes) = 4:39 PM

From the given statements:

“No snake is a bird” means there is no overlap between snakes and birds.
“Some birds are animals” means part of the bird set overlaps with the animal set.
“All animals need food” means everything in the animal set (and its overlaps) belongs to the larger “need food” set.

Now, looking at the conclusions:

• Conclusion I: “Some snakes need food.” — This does not follow, because there’s no information connecting snakes with animals or food. Whether snakes are animals or not can't be concluded from the given statements, and hence, we can’t conclude that they need food.

• Conclusion II: “No bird is a snake.” — This is true, as it directly restates the first statement (“No snake is a bird”).

Hence, only II follows. 

Statement I defines the event that the price of the crops has increased significantly in the last month. A price increase can be caused by a rise in demand or a decrease in supply. Statement II outlines that unseasonal heavy rains in the previous month have damaged the crops; it follows that this might have led to a reduction in the supply of the crops. The most suitable answer, therefore, is option B. Statement II is the cause and statement I is its effect.

Following is a Venn diagram defining the three classes, "scientists", "hardworking", and "well-paid".

Based on the given info, we can draw the following conclusions:

Since all scientists are hardworking, the inputs in the scientist circle that are outside the hardworking circle are zero. Since there are some hardworking people who are not well paid, the inputs a and b will be such that a+b>0. No other information can be known.

Statement I says that some scientists are not well-paid. This requires the value of b to be greater than zero. The best we can say is that a+b>0. Therefore, statement I does not follow.

Statement II says that some well-paid people are scientists, this requires the central input of the venn diagram to be greater than zero, which we cannot say anything of.

The correct answer is option D; neither 1 nor 2 follows.

This statement directly weakens the argument because it challenges the assumption that providing vocational training will actually improve employment rates. If many individuals who already possess such training remain jobless, it suggests that vocational training alone does not necessarily lead to employment opportunities. The problem, therefore, may lie not in the lack of skills but in the availability of suitable jobs or market demand. The correct answer should therefore be option (a)

The other options may pose difficulties or practical challenges, but they do not directly undermine the effectiveness of vocational training in improving employment, which is the central claim of the statement.  Option (b) only questions cost, not effectiveness; option (c) suggests preference for degrees but doesn’t prove training fails as some sectors still rely on skills; option (d) shows a lack of interest, not ineffectiveness, and the logic that training improves employability still stands.\

The statement tells us that the company has decided to lay off 20% of its workforce because of an economic recession. This action suggests that the company is attempting to reduce expenses and improve its financial position. However, while this decision may help relieve financial strain, it does not guarantee that the company will completely overcome its crisis, as several other factors, such as market conditions, demand, and management decisions, also play a role. Therefore, the conclusion that the company will now be able to overcome its financial crisis cannot be said to definitely follow, but it probably follows based on the intent behind the layoffs.
The correct choice is therefore option B.

The statement highlights a problem: the quality of primary education in government schools is poor, and many students are failing to acquire basic literacy and numeracy skills. It does not, however, make any comparison with private schools, nor does it imply that private schools offer better education. Therefore, assumption I is not implicit. 

Similarly, the statement does not assume that the government necessarily has the resources or ability to improve the situation; it merely identifies the issue. The possibility of government action is not mentioned or suggested. Hence, assumption II is also not implicit. The statement confines itself to expressing concern about the present state of affairs without implying either assumption.

So, the correct choice would be option D: Neither I nor II is implicit

The correct answer is (b) A major competitor launched a new model with superior features at a lower price during the same quarter. This option best explains why sales of the ‘Alpha’ brand remained stagnant despite increased marketing expenditure. A strong competitor offering a better product at a lower price would naturally attract potential customers, neutralising the impact of Alpha’s marketing push.

The other options are not correct because: Option (a) is irrelevant, as praise for creativity doesn’t guarantee sales impact. Option (c) could contribute to lower demand, but it doesn’t explain stagnation despite marketing as clearly as the competitor’s move does. Option (d) shows market growth but doesn’t explain why Alpha’s sales didn’t grow along with it.

Thus, (b) provides the most direct and logical explanation.

The passage argues that there is no consistent relationship between national budget deficits and trade deficits once data are adjusted for proper comparison. This means that changes in one (the budget deficit) do not predict changes in the other (the trade deficit). Therefore, it logically follows that lowering a country’s budget deficit does not necessarily lead to a reduction in its trade deficit. The correct answer is therefore option (c) Reducing a country’s national budget deficit will not necessarily result in a lowering of any trade deficit that country may have.

Option (a) is unsupported; the passage never mentions trade restrictions. Option (b) is the opposite of what’s stated; it says comparisons are possible when adjusted. Option (d) introduces population, which is irrelevant to the argument.

Hence, (c) is the only valid inference.

The correct answer is (b) Britain is democratic but not secular. This statement directly contradicts the claim that democracy cannot exist without secularism. If Britain, a well-known democracy, functions successfully despite not being secular, it serves as evidence that democracy can exist without secularism.

Option (a) shows a case where democracy failed despite secularism — it doesn’t prove the two can exist independently. Options (c) and (d) are irrelevant because both describe countries lacking democracy, which doesn’t test the link between democracy and secularism.

Hence, (b) clearly shows the original statement to be false.

Let the incomes of P, Q, and R be $$p,q$$ and $$r,$$ respectively.

We are given that the value of $$q$$ is $$25\%$$ less than $$r$$. So, the value of $$q$$ can be written as,

$$q\ =\left(1\ -\ \dfrac{25}{100}\right)r=\dfrac{3}{4}r$$.

We are also given that $$p$$ is $$20\%$$ higher than $$q$$. So, the value of $$p$$ can be written as,

$$p=\left(1\ +\ \dfrac{20}{100}\right)q=\dfrac{6}{5}q=\dfrac{6}{5}\times\ \dfrac{3}{4}r=\dfrac{9}{10}r$$

The percentage by which the salary of $$p$$ is less than $$r$$ can be calculated as,

Percentage $$=$$ $$\dfrac{r\ -\ p}{r}\times\ 100\ =\ \dfrac{\left(r\ -\ \dfrac{9}{10}r\right)}{r}\times\ 100\ =\ \dfrac{1}{10}\times\ 100\ =\ 10\%$$

Hence, the correct answer is option B.

For an amount to become three times itself, the interest gained on that amount must be twice its value.

Let the value of the amount be P, and the number of years it takes for the interest gained on that amount is 2P can be calculated as,

$$SI=\dfrac{P\times\ T\times\ R}{100}$$

$$2P=\dfrac{P\times\ T\times\ 25}{100}$$

$$T\ =\ 8$$ years.

Therefore, the time it takes for the amount to become three times its value is 8 years.

Hence, the correct answer is option B.

Let the three numbers be $$a,b$$ and $$c$$ in decreasing order. 

Half of the average of these 3 numbers is,

$$\dfrac{1}{2}\times\ \dfrac{a\ +\ b\ +\ c}{3}\ =\ 20$$

$$\ a\ +\ b\ +\ c\ =\ 120$$ --(1)

We can see that the first number mentioned is the highest in the question, and its value is given to be,

$$a=2b$$ --(2)

The second number value is given to be,

$$b=3c$$ --(3)

So, the value $$a$$ can also be written as, 

$$a=2b=2*3c=6c$$ --(4)

Substituting (3) and (4) in (1), we get,

$$6c+3c+c=120$$

$$10c=120$$

$$c=12$$

$$a=6c=72$$

Sum of smallest and largest numbers can be calculated as,

$$a+c=72+12=84$$.

Hence, the correct answer is option C.

Let the scheduled time be T and the distance that needs to be travelled be D.

While travelling at 50kmph, the train covers D in (T - 1) hours. The value D can also be written as,

D = speed * time = 50kmph * (T - 1)

We are also given that when the train runs at 8.33 m/s = $$\dfrac{25}{3}$$m/s = $$\dfrac{25}{3}\times\ \dfrac{18}{5}\ =\ 30$$kmph, train covers the distance is (T + $$\dfrac{300}{60}$$) hours = (T + 5) hours. The value of D can also be written as,

D = speed * time = 30kmph * (T + 5)

Equating both the values of D, we get,

50T - 50 = 30T + 150

20T = 200

T = 10 hours.

So, the correct time for the train to complete the journey is 10 hours.

Hence, the correct answer is option A.

The total area of square $$=\ S^2\ =\ \left(150cm\right)^2\ =\ 22500cm^2$$

The area of the parts cut from the edges $$=\ 4\ \times\ \dfrac{1}{4}\ \times\ \dfrac{22}{7}\ \times\ \left(14cm\right)^2\ =\ 22\ \times\ 14\ \times\ 2\ =\ 616\ cm^2\ $$

Area remaining $$=22500-616=21884\ cm^2$$

Hence, the correct answer is option C.

Let the total amount of work that needs to be done be $$W$$, and the efficiencies of $$A$$ and $$B$$ be $$a$$ and $$b$$, respectively. 

The amount of work done by $$A$$ and $$B$$ together in 12 days is,

$$12(a+b)=W$$ --(1)

The amount of work done by $$A$$ alone in 18 days is,

$$18(a)=W$$

$$a=\dfrac{W}{18}$$ --(2)

Substituting (2) in (1), we get,

$$12\left(\dfrac{W}{18}\ +\ b\right)\ =\ W$$

$$\dfrac{2W}{3}\ +\ 12b\ =\ W$$

$$12b\ =\ \dfrac{W}{3}$$

$$W\ =\ 36b$$

So, $$B$$ alone can complete the total work in 36 days.

Hence, the correct answer is option B.

Roots of a quadratic equation $$ax^2\ +\ bx\ +\ c\ =\ 0$$ can be calculated using the formula,

Roots $$=\ \dfrac{-b\ \pm\ \sqrt{\ b^2\ -\ 4ac}}{2a}$$

Roots of $$x^2−7x+12=0$$ can be calculated as,

Roots $$=\ \dfrac{-\left(-7\right)\ \pm\ \sqrt{\ \left(-7\right)^2\ -\ 4\left(1\right)\left(12\right)}}{2\left(1\right)}\ =\ \dfrac{7\ \pm\ \sqrt{\ 49\ -\ 48}}{2}\ =\ \dfrac{7\ \pm\ 1}{2}\ =\ \dfrac{7\ +\ 1}{2}\ or\ \dfrac{7\ -\ 1}{2}\ =\ 4\ or\ 3$$

So, the roots of the equation are (3, 4)

Hence, the correct answer is option A.

To find this number, we must first find the Least Common Multiple (LCM) of the divisors (12, 18, 27) and then add the required remainder 9.

Step 1: To find the LCM of 12, 18, and 27

We use prime factorisation to find the LCM:

• $$12=2^2\times3^1$$
• $$18 = 2^1 \times 3^2$$
• $$27 = 3^3$$

The LCM is the product of the highest power of all prime factors:

$$\text{LCM}(12, 18, 27) = 2^2 \times 3^3$$

$$\text{LCM} = 4 \times 27$$

$$\text{LCM} = 108$$

Step 2: Add the Remainder

The required number is (LCM) + (Remainder).

$$\text{Required Number} = 108 + 9$$

$$\text{Required Number} = 117$$

Hence, the correct answer is option A.

Let the initial length and breadth of the rectangle be $$L$$ and $$B$$.

We are told that the length is increased by 25% and the breadth is decreased by 20%. So, the new length and breadth become 

Length $$L\left(1\ +\dfrac{25}{100}\right)\ =\ \dfrac{5}{4}L$$

Breadth $$=\ B\left(1\ -\ \dfrac{20}{100}\right)\ =\ \dfrac{4}{5}B$$

Initial Area $$=\ L\times\ B$$

Final Area $$=\ \dfrac{5}{4}L\times\ \dfrac{4}{5}B\ =\ L\ \times\ B$$

We can see that there is no change in the Area. So the percentage change in area is 0%.

Hence, the correct answer is option A.

If the sum ₹12,000 is divided between A, B, and C in the ratio 2:3:5, then the share of B can be calculated as,

B's share $$=\ \dfrac{3}{2\ +\ 3\ +\ 5}\ \times\ 12000\ =\ \dfrac{3}{10}\times\ 12000\ =\ 3600$$

So, B's share is ₹3,600.

Hence, the correct answer is option B.

We know that when there are two dice thrown, there are 36 possible outcomes.

(1,1), (1,2)......(1,6)

(2,1), (2,2),.....(2,6)

..

(6,1), (6,2), .....(6,6)

We need to get a sum of 9

(3,6),(4,5),(5,4),(6,3)

Thus, there are four possibilities.

Therefore, the probability of getting a sum of 9 = 4/36 = 1/9

Option B is the correct answer.

A man covers a distance of 120 km at 40 km/h and returns at 60 km/h. What is his average speed?

A man covers a distance of 120 km at 40 km/h

Time taken = 120/40 = 3 hours

A man covers a distance of 120 km on the return journey at 60 km/h.

Time taken = 120/60 = 2 hours.

Average speed = Total distance travelled / Total time taken 

Average speed = 240/5 = 48 km/hr

The sum of three numbers in AP is 27.

Let us assume the numbers are a-d, a , a+d

Where d is the common difference.

Sum a-d+a+a+d = 27

3a = 27

a = 9

If 1 is added to the first number, 2 to the second, and 3 to the third, the new numbers are in GP.

So, the new numbers are 

9-d+1, 9+2, 9+d+2

10-d , 11, 11+d

Checking options:

A) 6, 9, 12 when we add numbers it becomes 7, 11, 15 (Not in GP)

B) 5, 9, 13 when we add numbers it becomes 6, 11, 16 (Not in GP)

C) 10, 9, 8 when we add numbers it becomes 11, 11, 11 (In GP)

D) 4, 9, 14 when we add numbers it becomes 5, 11, 17 (Not in GP)

Hence, answer is option C.

We know that the product of two numbers = the product of HCF and LCM

The HCF of two numbers is 15, and the LCM is 360.

If one number is 45

Assuming the other number to be N

Therefore, 15*360 = 45*N

Thus, N = 120

An electric pump can fill a cistern in 6 hours.

Assuming the capacity of the cistern to be 90 litres.

Thus, the electric pump can fill the cistern 90 litres in 6 hours or 15 litres in one hour.

Because of a leak in the cistern, it was taking 9 hrs to fill the cistern.

Therefore, the total volume filled in 1 hour = 90/9 = 10 litres per hour.

We know the pump can fill 15 litres in one hour; therefore, because of the leak, 5 litres of water are removed every hour.

If the tank is filled, it contains 90 litres.

The time taken by the leak to empty = 90/5 = 18 hours.

495 is not divisible by 7, so we can eliminate it.

455 and 490 are not divisible by 3, since a number is divisible by 3 only if the sum of its digits is divisible by 3.

Hence, 420 is the correct answer.