If a train runs at 50 km/hr, it reaches 60 minutes earlier than its schedule time at its destination but if it runs at 8.33 m/s it reaches at its destination 300 minutes late, find the correct time for the train to complete its journey.

Let the scheduled time be T and the distance that needs to be travelled be D.

While travelling at 50kmph, the train covers D in (T - 1) hours. The value D can also be written as,

D = speed * time = 50kmph * (T - 1)

We are also given that when the train runs at 8.33 m/s = $$\dfrac{25}{3}$$m/s = $$\dfrac{25}{3}\times\ \dfrac{18}{5}\ =\ 30$$kmph, train covers the distance is (T + $$\dfrac{300}{60}$$) hours = (T + 5) hours. The value of D can also be written as,

D = speed * time = 30kmph * (T + 5)

Equating both the values of D, we get,

50T - 50 = 30T + 150

20T = 200

T = 10 hours.

So, the correct time for the train to complete the journey is 10 hours.

Hence, the correct answer is option A.