SBI Associate Clerk 2008

Digits 5 1 3 4 9 6 8 2 7
code P A K % R @ D © M
Conditions:
(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
(ii) If both the first and the last digits are even both are to be coded as $$\bigstar$$
(iii) If both the first and the last digits are odd both are to be coded as $.

Here, first digit is even and last digit is odd. Therefore, no conditions can be applied.

The data given to us is:

Digits 5 1 3 4 9 6 8 2 7
code P A K % R @ D © M
Conditions:
(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
(ii) If both the first and the last digits are even both are to be coded as $$\bigstar$$
(iii) If both the first and the last digits are odd both are to be coded as $.

Both first and last will be coded as $$\bigstar$$

Now, after coding, we get,

$$\bigstar$$MA©P$$\bigstar$$ which is option C

The data given to us is:

Digits 5 1 3 4 9 6 8 2 7
code P A K % R @ D © M
Conditions:
(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
(ii) If both the first and the last digits are even both are to be coded as $$\bigstar$$
(iii) If both the first and the last digits are odd both are to be coded as $.

Here, by choosing proper symbols, we get code as: DAK%@R.

The data given to us is:

Digits 5 1 3 4 9 6 8 2 7
code P A K % R @ D © M
Conditions:
(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
(ii) If both the first and the last digits are even both are to be coded as $$\bigstar$$
(iii) If both the first and the last digits are odd both are to be coded as $.

As both the digits are odd, they can be coded as $.

Only option D has $ at the end. Hence, the correct option is D.

The data given to us is:

Digits 5 1 3 4 9 6 8 2 7
code P A K % R @ D © M
Conditions:
(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
(ii) If both the first and the last digits are even both are to be coded as $$\bigstar$$
(iii) If both the first and the last digits are odd both are to be coded as $.

Here, 5 is odd and 6 is even, there symbols would be reversed.
591426 would be coded as @RA%©P

Hence, option A is correct.

The data provided to us is:

A,B,C,D,E,F,G and H are sitting around a circle facing at the center. D is second to the left of F and third to the right of H. A is second to the right of F and on immediate neighbour of H C is second to the right of B and F is third to the right of B. G is not an immediate neighbour of F.

This can be intrepreted as:

There are 3 members between H and C.

Option B is correct.
 

The data provided to us is:

A,B,C,D,E,F,G and H are sitting around a circle facing at the center. D is second to the left of F and third to the right of H. A is second to the right of F and on immediate neighbour of H C is second to the right of B and F is third to the right of B. G is not an immediate neighbour of F.

This can be intrepreted as:

To immediate left of A is E.

The data provided to us is:

A,B,C,D,E,F,G and H are sitting around a circle facing at the center. D is second to the left of F and third to the right of H. A is second to the right of F and on immediate neighbour of H C is second to the right of B and F is third to the right of B. G is not an immediate neighbour of F.

This can be intrepreted as:

Here, nowhere in the given pairs, is the first person sitting to the immediate left of the second person.

The data provided to us is:

A,B,C,D,E,F,G and H are sitting around a circle facing at the center. D is second to the left of F and third to the right of H. A is second to the right of F and on immediate neighbour of H C is second to the right of B and F is third to the right of B. G is not an immediate neighbour of F.

This can be intrepreted as:

E is fourth to the right of B.

The data provided to us is:

A,B,C,D,E,F,G and H are sitting around a circle facing at the center. D is second to the left of F and third to the right of H. A is second to the right of F and on immediate neighbour of H C is second to the right of B and F is third to the right of B. G is not an immediate neighbour of F.

This can be intrepreted as:

E is third to the left of G.