AKSHAY KUMAR
3 years, 3 months ago
Question
Three positive numbers p, q and r are in AP such that p*q*r = 64. Find the minimum value of q.
A
2(1/3)
B
2(2/3)
C
22
D
2(4/3)
Maruti Konduri
3 years ago
Let the three numbers be q-d, q, q+d
Therefore, q*(q^2-d^2) = 64
For q to be minimum, d has to be 0.
Hence, the minimum value of q is cube root of 64 = 4
