Question Three positive numbers p, q and r are in AP such that p*q*r = 64. Find the minimum value of q. A 2(1/3) B 2(2/3) C 22 D 2(4/3)

Let the three numbers be q-d, q, q+d
Therefore, q*(q^2-d^2) = 64
For q to be minimum, d has to be 0.

Hence, the minimum value of q is cube root of 64 = 4