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4 years ago
Three positive numbers p, q and r are in AP such that p*q*r = 64. Find the minimum value of q.
3 years, 9 months ago
Let the three numbers be q-d, q, q+d Therefore, q*(q^2-d^2) = 64For q to be minimum, d has to be 0.
Hence, the minimum value of q is cube root of 64 = 4
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