PQRS is a cyclic quadrilateral in which PQ is 14.4,QR is 12.8 ,SR is 9.6.If PR bisects QS,what is the lengh of PS?

Question

Amit Gautam · Answer

19.2

arun baswal · Answer

19.2 is thee length of ps..... direct formula of this case is pq*qr=rs*ps

Nancy Sharma · Answer

how do we get to know that we have to take PQ×QR=SR×PS and not QR×SR=PQ×PS???

sumit chaudhary · Answer

PQofQR=SRofPS =19.2

Rohee Tiwari · Answer

19.2

priyam dubey · Answer

side ke ratio me hi

Vikash Gupta · Answer

All sides ratio is equal so that answer is 1 19.2

Dipanjan Chattakhandi · Answer

The length of PS is equal to QR= 12.8. 
Proof: Suppose the two diagonals PR and QS bisect at O. Then since the diagonal bisects QS so PO=OR, OS=OQ and angle POS= angle QOR (vertically opposite) So the two triangles are congruent (SAS congruency) So QR=PS

PQRS is a cyclic quadrilateral in which PQ is 14.4,QR is 12.8 ,SR is 9.6.If PR bisects QS,what is the lengh of PS?

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