PQRS is a cyclic quadrilateral in which PQ is 14.4,QR is 12.8 ,SR is 9.6.If PR bisects QS,what is the lengh of PS?

19.2

19.2 is thee length of ps..... direct formula of this case is pq*qr=rs*ps

how do we get to know that we have to take PQ×QR=SR×PS and not QR×SR=PQ×PS???

PQofQR=SRofPS =19.2

19.2

side ke ratio me hi

All sides ratio is equal so that answer is 1 19.2

The length of PS is equal to QR= 12.8.
Proof: Suppose the two diagonals PR and QS bisect at O. Then since the diagonal bisects QS so PO=OR, OS=OQ and angle POS= angle QOR (vertically opposite) So the two triangles are congruent (SAS congruency) So QR=PS