pavun, siresh and mayank are three brothers. pavun and suresh are twins. the sum of ages ofpavun and suresh is same as that of mayanks alone.. four year earlier the ratio of age of pavun and mayank was 3:8. what will be the age of suresh 4 ywars hence?

Four years earlier, ages were:
Pavun: 6, Suresh: 6, Mayank: 16

At present, ages are:
Pavun: 10, Suresh: 10, Mayank: 20

Therefore, after 4 years, Suresh will be 14 years old (10+4)

This can be calculated as follows:
Let age of Pavun and Suresh be x, age of Mayank be y.

From the statements, we know:

A) 2x=y, Thus 2x - y = 0
B) x-4:y-4 = 3:8
which turns out to be 8x - 3y = 20

If we compare 2x - y = 0 and 8x - 3y = 20, we get x = 10.

So, present age of Suresh = 10 (which is x)
4 years hence, Suresh will be 10 + 4 = 14 years old.
I hope I explained it.