NICL Administrative Officer (AO) 2013 Question Paper Solved

Let the integers be x and y.
x^2+y^2 = 100
x^2 - y^2 = 28
2x^2 = 128
x^2 = 64
x = 8
Therefore, y=6
x+y = 8+6 =14
Therefore, the correct option is option C.

 

Let the work be W and speed of each man be x.
W/(8x) = 40
x = W/320
If two more men join, total speed will become = W/32
Now, the work can be done= W/(W/32) = 32 days
Therefore work will be done in 32 days.
 

Let the speed of Women be x and that of children be y. Let piece of work be W.
10x=W/7, x=W/70
10y =W/14 y= W/140
Now, 5x + 10y = W/14 + W/14 = W/7
Number of day srequired to complete the work = W/(W/7) = 7 days.
Therefore, the correct option is option C.
 

This can be represented in diagrammatic form as,
 

Hence, by 30-60-90 theorem
Side opposite to 60 degree angle = $$\sqrt{3}$$/2 *hypotenuse = $$\sqrt{3}$$/2 *10 = 8.66 m

Therefore, the correct option is option C.
 

Let the numbers be a, b, c, d, and e.

a+b+c+d+e = 555
Now, (a+b)/2 = 75
a+b = 150
and c = 115
therefore, d+e = 290
Average, (d+e)/2 = 145

Let temperature on monday be a and that on thursday be y.
(x+y)/2 = 36
Now, y = 0.8x
Hence, we get Monday's temperature as 40
Therefore, none of these is the answer.

 

The express train will cover 600 km in 6hrs and will stop fo 21 minutes in total at different stops.
Now, the distance covered by the local train in 6 hours 21 minutes while subtracting the 1 minute for each halt after 25 minutes = 6.35 * 50 - 250/25 = 307.5 km.

Therfore, the correct option is option A.

Initially, let us assume that the price of sugar was Rs.100/kg.
Now, after the increase the price is Rs120/kg.
A person can buy 1kg of sugar for Rs.120.
He can buy xkg of sugar for Rs.100
Hence, x=(100/120) = 5/6
reduction in consumption = (1/6)
Ratio of reduction in consumption to original consumption = 1:6
Hence, the correct option is option C.
 

The given series is: $$\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+.......+\frac{1}{(n+1)}$$
This can be reframed as: $$\frac{1}{1}n-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}........+\frac{1}{n+1}$$ = $$\frac{1}{1}-\frac{1}{n+1}$$ = $$\frac{n}{n+1}$$
Therefore, the correct option is option D.