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Question 81
The sum of the squares of two positive integers is 100 and the difference of their squares is 28. The sum of the numbers is
Solution
Let the integers be x and y.
x^2+y^2 = 100
x^2 - y^2 = 28
2x^2 = 128
x^2 = 64
x = 8
Therefore, y=6
x+y = 8+6 =14
Therefore, the correct option is option C.
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