Question 78

The perimeter of a circular and a square field are equal. What is the diameter of the circular field, if the area of the square field is 484 $$metre^{2}$$

Solution

Let the square of side be x,
Now area = 484
x^2 = 484, x=22
Perimeter = 4*22= 88
Circumference = 88
2*(22/7)*r = 88
Hence, r=14
Area= (22/7)*14*14 =616
Therefore, option C is correct.

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The perimeter of a circular and a square field are equal. What is the diameter of the circular field, if the area of the square field is 484 $$metre^{2}$$

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