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8 years, 4 months ago
8 years, 4 months ago
Since 2N and 3N have different number of factors, so number N must have 2's in it. On factorising of 28 (14*2, 7*4, 28*1) we can observe that N must be 2^5*3^3.
So 6N would be 2^6*3^4 . Hence the number of factors will be 7*5 = 35. Option B
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