Let A,B,C be three positive integers such that the sum of A and the mean of B&C is 5. also,, the sum of B and the mean of A&C is 7. what is the sum of A and B ?

6

6

4

can anyone explain with solution.. it'd be helpful.. thanks..

yes. see there would be two equations formed in total if we see the from the 1st hint 1st equation would be A + (B+C)/2 = 5 simplfying this 2A+B+C=10 Likewise 2nd equation would be from 2nd hint this would be simplifies to A+2B+C=14 Now if you subtract equation 1 from 2 B- A =4 ( you would get this ) so B is 4 more than A Now it is given that A , B and C are positive integers suppose I take least value for A as 1 B would be 5 then because B is 4 more than A and if you put these values in any of the equations you would get C as 3 if I take any other case say A =2 , then C would become 0 and c is positive integer so any other value wont satisfy this A- 1 , B-5 and C-3 A+b = 6 answer