Let A,B,C be three positive integers such that the sum of A and the mean of B&C is 5.
also,, the sum of B and the mean of A&C is 7.what is the sum of A and B ?

yes.
see
there would be two equations formed in total
if we see the from the 1st hint
1st equation would be
A + (B+C)/2 = 5
simplfying this
2A+B+C=10
Likewise
2nd equation would be from 2nd hint
this would be simplifies to A+2B+C=14
Now if you subtract equation 1 from 2
B- A =4 ( you would get this )
so B is 4 more than A
Now it is given that A , B and C are positive integers
suppose I take least value for A as 1
B would be 5 then because B is 4 more than A
and if you put these values in any of the equations you would get C as 3
if I take any other case
say A =2 , then C would become 0 and c is positive integer
so any other value wont satisfy this
A- 1 , B-5 and C-3
A+b = 6 answer

can anyone explain with solution.. it'd be helpful..
thanks..

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