in a peremutation and combination if 7 different balls are placed in 3 different boxes we take it as each ball has 3 options to place in 3 different boxes and total no of conditions are 3 power 7 but why not we take it as in the 3 boxes each box has filled with 7 different type of balls and total n…

Question

in a peremutation and combination if 7 different balls are placed in 3 different boxes we take it as each ball has 3 options to place in 3 different boxes and total no of conditions are 3 power 7 but why not we take it as in the 3 boxes each box has filled with 7 different type of balls and total no of conditions are 7 cube

Puja R V · Answer

In the first case, multiple balls can be placed in the same box, but in second case, multiple boxes can't be given to same ball. That is why.

Hope that helps.

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