If the area of the circle is increased by 21% , then what is the percentage increased in the circumference of the circle?

Question

Ayush kumar · Answer

10% -- &gt; r1 = 1.21r2 -&gt; 2.2pier1 - 2pier2 / 2pier2 *100 = 10%

Vergil · Answer

Let R be the final radius and r be the initial radius. Then, Pi*R^2/Pi*r^2=1.21=1.1^2
=&gt;R/r=1.1=&gt;2Pi*R/2Pi*r=1.1. Hence, growth of 10%.

RiTu Raj PaTeL · Answer

10%

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