If log 242= a, log 80 = b, log45=c, express log36 in terms of a,b and c

Hi Sakshi,
This question seems to be complete but can be solved by assuming all logs in base 10.
a = log 242 = 2log 11 + log 2
b = log 80 = 2log 2 + 2log 2 + log 5 ....... (1)
c = log 45 = 2log 3 + log 5 ....... (2)
Adding (1) and (2), we get
b + c = 2log6 + 2log 2 + 2log 5
b + c = log 36 + 2
log 36 = b + c - 2
Hope this helps!