If log 242= a, log 80 = b, log45=c, express log36 in terms of a,b and c

Hi Sakshi, This question seems to be complete but can be solved by assuming all logs in base 10. a = log 242 = 2log 11 + log 2 b = log 80 = 2log 2 + 2log 2 + log 5 ....... (1) c = log 45 = 2log 3 + log 5 ....... (2) Adding (1) and (2), we get b + c = 2log6 + 2log 2 + 2log 5 b + c = log 36 + 2 log 36 = b + c - 2 Hope this helps!