if a+b+c=6 and ab+bc+ca= 1 than find ab(b+a)+bc(c+b)+ac(a+c)+3abc

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ab(b+a)+bc(b+c)+ac(a+c)=ab(6-c)+bc(6-a)+ac(6-b)+3abc
=6ab-abc+6bc-abc+6ca-abc+3abc
=6(ab+bc+ca)-3abc+3abc
=6(1)=6

ab(b+a+c) + bc(c+b+a) + ac(a+c+b)
=
6(ab+bc+ca) = 6

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