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1 year, 11 months ago
1 year, 11 months ago
if it is given that (c+d) > 0 or c,d are greater than 0, then, on adding both equations we get, (a+b)+ (1/(c+d)) +(c+d) + (1/(e+f)) = 2 and applying AM > = GM on middle 2 terms we get, (1/(c+d))+(c+d) >= 2, this implies that (a+b) and (e+f) must be 0 which means the value of (a+b)(c+d)(e+f) must be 0.<br>Hope that helps.<br>
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